higher order delays and delyN
higher order delays and delyN
I construct an aging chain with 3 serial stocks. Every outflow is stock*delaytime, the first inflow is a pulse. Thus the third stock should represent a daly of third order.
Then I compare this last stock with a delayN(inflow,delaytime,0,3).
Both aren't the same. Even if I take another delaytime for the delayN function I cannot define it such that the graph of the third order delay and that one of the delay3 become congruent.
Where is my error in reasoning?
Then I compare this last stock with a delayN(inflow,delaytime,0,3).
Both aren't the same. Even if I take another delaytime for the delayN function I cannot define it such that the graph of the third order delay and that one of the delay3 become congruent.
Where is my error in reasoning?
aging chain
Hi Addor
Can you join a simplistic model to illustrate your problem?
Regards.
JJ
Can you join a simplistic model to illustrate your problem?
Regards.
JJ
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nth order delay
So, you confirm, that a third order delay should be the same as a delay3(...).
I used a delay time of 0.5 for each of 7 stocks but 7*0.5 for the delay3. This should also be valid, shouldn't it?
Strange is, that the delay3 gives "pieces/hour" instead of "pieces" as dimension....
Here is my model
I used a delay time of 0.5 for each of 7 stocks but 7*0.5 for the delay3. This should also be valid, shouldn't it?
Strange is, that the delay3 gives "pieces/hour" instead of "pieces" as dimension....
Here is my model
- Attachments
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- delayN.mdl
- (5.67 KiB) Downloaded 599 times
third order delay
I think I should multiply the dealytime in delay3(...) not with 7 but with 3. But then the difference between stock3 and delay3(..) is even greater....
Peter
Peter
Peter Addor
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Of course, Bob, I did it. I attache here the model that uses the intermediate delaytime for the stocks. Still delay3 and stock3 are different, and although the input has the dimension "pieces/hour" and the delaytime has dimension "hour" delay3 get the dimension "pieces/hour".
Also after reading the manual I don't see my error in reasoning. I'm sorry.
Peter
Also after reading the manual I don't see my error in reasoning. I'm sorry.
Peter
Peter Addor
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Of course, Bob, I should know how to handle compound fractions.... it's a shame
Now I have the "total delaytime" and the "delaytime = total delaytime / 7"
But nevertheless delay3 isn't same as stock3
And why gives delay3 as units "pieces/hour" if the input has "pieces/hour" and the "delaytime" has hour?
Now I have the "total delaytime" and the "delaytime = total delaytime / 7"
But nevertheless delay3 isn't same as stock3
And why gives delay3 as units "pieces/hour" if the input has "pieces/hour" and the "delaytime" has hour?
- Attachments
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- delayN.mdl
- (5.76 KiB) Downloaded 635 times
Peter Addor
Ok, I built a model once again (only with 3 levels in the aging chain), and now delay3, delayN(...3) and stock3 are indeed same. I don't know what happend in the model before. Somethings went wrong.
But still I get the units/hour as the dimensions of delay...
But still I get the units/hour as the dimensions of delay...
- Attachments
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- delay3level.mdl
- (3.31 KiB) Downloaded 703 times
Peter Addor
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